(x-8)(3x-5)=3x^2-18

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Solution for (x-8)(3x-5)=3x^2-18 equation:



(x-8)(3x-5)=3x^2-18
We move all terms to the left:
(x-8)(3x-5)-(3x^2-18)=0
We get rid of parentheses
-3x^2+(x-8)(3x-5)+18=0
We multiply parentheses ..
-3x^2+(+3x^2-5x-24x+40)+18=0
We get rid of parentheses
-3x^2+3x^2-5x-24x+40+18=0
We add all the numbers together, and all the variables
-29x+58=0
We move all terms containing x to the left, all other terms to the right
-29x=-58
x=-58/-29
x=+2

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